Advertisements
Advertisements
Question
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
Advertisements
Solution

Let number of sides of regular polygon = n
AB & DC when produced meet at P such that
∠P = 90°
∵ Interior angles are equal.
∴ ∠ABC = ∠BCD
∴ 180° - ∠ABC = 180° - ∠BCD
∴ ∠PBC = ∠BCP
But ∠P = 90° (given)
∴ ∠PBC + ∠BCP = 180° - 90° = 90°
∴ ∠PBC =∠BCP
`= 1/2 XX 90° = 45°`
∴ Each exterior angle = 45°
`therefore 45^circ = 360^circ/"n"`
n = `360^circ/45^circ`
n = 8
APPEARS IN
RELATED QUESTIONS
Is it possible to have a regular polygon whose interior angle is : 170°
Is it possible to have a regular polygon whose interior angle is:
138°
Is it possible to have a regular polygon whose each exterior angle is: 40° of a right angle.
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides in the polygon.
Calculate the number of sides of a regular polygon, if: its exterior angle exceeds its interior angle by 60°.
Find the number of sides in a regular polygon, if its interior angle is: 150°
Is it possible to have a regular polygon whose exterior angle is: 100°
What is the measure of each interior angle of a regular hexagon?
Which formula correctly represents the sum of interior angles of an n-sided polygon?
