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Question
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
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Solution
Each exterior angle = `2/5` of a right angle
`= 2/5 xx 90 ^circ`
= 36°
Let number of sides = n
`therefore 360^circ/"n" = 36^circ`
`therefore "n" = 360^circ/36^circ`
n = 10
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| (v) _________ | __________ | _____150°_____ |
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