Advertisements
Advertisements
प्रश्न
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
Advertisements
उत्तर
Each exterior angle = `2/5` of a right angle
`= 2/5 xx 90 ^circ`
= 36°
Let number of sides = n
`therefore 360^circ/"n" = 36^circ`
`therefore "n" = 360^circ/36^circ`
n = 10
APPEARS IN
संबंधित प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 135°
Is it possible to have a regular polygon whose each exterior angle is: 80°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The ratio between the interior angle and the exterior angle of a regular polygon is 2: 1. Find:
(i) each exterior angle of the polygon ;
(ii) number of sides in the polygon.
The sum of interior angles of a regular polygon is thrice the sum of its exterior angles. Find the number of sides in the polygon.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Find number of side in a regular polygon, if it exterior angle is: 36
Is it possible to have a regular polygon whose interior angle is: 155°
Is it possible to have a regular polygon whose exterior angle is: 36°
What is the sum of all exterior angles of any regular polygon?
