Advertisements
Advertisements
प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 135°
Advertisements
उत्तर
No. of. sides = n
Each interior angle = 135°
`("n" - 2)/"n" xx 180^circ = 135^circ`
180n - 360° = 135n
180n - 135n = 360°
45n = 360°
n = 8
APPEARS IN
संबंधित प्रश्न
Is it possible to have a regular polygon whose interior angle is:
138°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The measure of each interior angle of a regular polygon is five times the measure of its exterior angle. Find :
(i) measure of each interior angle ;
(ii) measure of each exterior angle and
(iii) number of sides in the polygon.
The sum of interior angles of a regular polygon is twice the sum of its exterior angles. Find the number of sides of the polygon.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
If the difference between the exterior angle of a 'n' sided regular polygon and an (n + 1) sided regular polygon is 12°, find the value of n.
Is it possible to have a regular polygon whose exterior angle is: 36°
If each interior angle of a regular polygon is 144°, what is its corresponding exterior angle?
What is the sum of all exterior angles of any regular polygon?
