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प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: `1 1/5` of a right angle
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उत्तर
No. of. sides = n
Each interior angle = `1 1/5` right angles
= `6/5 xx 90`
= 108°
`therefore ("n" - 2)/"n" xx 180^circ = 108^circ`
180n - 360° = 108n
180n - 108n = 360°
72n = 360°
n = 5
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संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides in the polygon.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
If the difference between the exterior angle of a 'n' sided regular polygon and an (n + 1) sided regular polygon is 12°, find the value of n.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Is it possible to have a regular polygon whose interior angle is: 135°
Is it possible to have a regular polygon whose interior angle is: 155°
What is the measure of each interior angle of a regular hexagon?
Which formula correctly represents the sum of interior angles of an n-sided polygon?
