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प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: `1 1/5` of a right angle
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उत्तर
No. of. sides = n
Each interior angle = `1 1/5` right angles
= `6/5 xx 90`
= 108°
`therefore ("n" - 2)/"n" xx 180^circ = 108^circ`
180n - 360° = 108n
180n - 108n = 360°
72n = 360°
n = 5
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संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
Find the number of sides in a regular polygon, if its interior angle is: 160°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The ratio between the exterior angle and the interior angle of a regular polygon is 1 : 4. Find the number of sides in the polygon.
The difference between the exterior angles of two regular polygons, having the sides equal to (n – 1) and (n + 1) is 9°. Find the value of n.
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Is it possible to have a regular polygon whose exterior angle is: 100°
What is the measure of each interior angle of a regular hexagon?
If each interior angle of a regular polygon is 144°, what is its corresponding exterior angle?
