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प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 135°
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उत्तर
No. of. sides = n
Each interior angle = 135°
`("n" - 2)/"n" xx 180^circ = 135^circ`
180n - 360° = 135n
180n - 135n = 360°
45n = 360°
n = 8
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संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
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Is it possible to have a regular polygon whose each exterior angle is: 80°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
If the difference between the exterior angle of a 'n' sided regular polygon and an (n + 1) sided regular polygon is 12°, find the value of n.
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Is it possible to have a regular polygon whose interior angle is: 155°
Is it possible to have a regular polygon whose exterior angle is: 36°
