Advertisements
Advertisements
प्रश्न
The measure of each interior angle of a regular polygon is five times the measure of its exterior angle. Find :
(i) measure of each interior angle ;
(ii) measure of each exterior angle and
(iii) number of sides in the polygon.
Advertisements
उत्तर
Let exterior angle = x°
Interior angle = 5x°
x + 5x = 180°
6x = 180°
x = 30°
Each exterior angle = 30°
Each interior angle = 5 x 30° = 150°
Let no. of sides = n
∵ each exterior angle = `360^circ/"n"`
`30^circ = (360^circ)/"n"`
n = `(360^circ)/30^circ`
n = 12
Hence (i) 150° (ii) 30° (iii) 12
APPEARS IN
संबंधित प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 160°
Find the number of sides in a regular polygon, if its exterior angle is : `1/3` of right angle
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
Is it possible to have a regular polygon whose interior angle is : 170°
Is it possible to have a regular polygon whose interior angle is:
138°
Is it possible to have a regular polygon whose each exterior angle is: 80°
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Calculate the number of sides of a regular polygon, if: its exterior angle exceeds its interior angle by 60°.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
If each interior angle of a regular polygon is 144°, what is its corresponding exterior angle?
