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प्रश्न
Is it possible to have a regular polygon whose interior angle is: 135°
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उत्तर
No. of. sides = n
Each interior angle = 135°
∴ `(("2n" - 4) xx 90^circ)/"n" = 135^circ`
180n - 360° = 135n
180n - 135n = 360°
n = `(360°)/(45°)`
n = 8
Which is a whole number.
Hence, it is possible to have a regular polygon whose interior angle is 135°.
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संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
Find the number of sides in a regular polygon, if its interior angle is: 135°
The sum of interior angles of a regular polygon is twice the sum of its exterior angles. Find the number of sides of the polygon.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
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The difference between the exterior angles of two regular polygons, having the sides equal to (n – 1) and (n + 1) is 9°. Find the value of n.
Three of the exterior angles of a hexagon are 40°, 51 ° and 86°. If each of the remaining exterior angles is x°, find the value of x.
Calculate the number of sides of a regular polygon, if: its interior angle is five times its exterior angle.
Is it possible to have a regular polygon whose exterior angle is: 100°
What is the measure of each interior angle of a regular hexagon?
