Advertisements
Advertisements
प्रश्न
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
Advertisements
उत्तर

Let number of sides of regular polygon = n
AB & DC when produced meet at P such that
∠P = 90°
∵ Interior angles are equal.
∴ ∠ABC = ∠BCD
∴ 180° - ∠ABC = 180° - ∠BCD
∴ ∠PBC = ∠BCP
But ∠P = 90° (given)
∴ ∠PBC + ∠BCP = 180° - 90° = 90°
∴ ∠PBC =∠BCP
`= 1/2 XX 90° = 45°`
∴ Each exterior angle = 45°
`therefore 45^circ = 360^circ/"n"`
n = `360^circ/45^circ`
n = 8
APPEARS IN
संबंधित प्रश्न
Is it possible to have a regular polygon whose interior angle is:
138°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides in the polygon.
The measure of each interior angle of a regular polygon is five times the measure of its exterior angle. Find :
(i) measure of each interior angle ;
(ii) measure of each exterior angle and
(iii) number of sides in the polygon.
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Calculate the number of sides of a regular polygon, if: the ratio between its exterior angle and interior angle is 2: 7.
Find the number of sides in a regular polygon, if its interior angle is: 150°
Is it possible to have a regular polygon whose interior angle is: 155°
What is the sum of all exterior angles of any regular polygon?
Which formula correctly represents the sum of interior angles of an n-sided polygon?
