Question

Three of the exterior angles of a hexagon are 40°, 51 ° and 86°. If each of the remaining exterior angles is x°, find the value of x.

Answer 1

The sum of all exterior angles of any polygon is always: 360^∘

The total of the six exterior angles is: 40^∘ + 51^∘ + 86^∘ + x + x + x = 360^∘

Simplify: 177^∘ + 3x = 360^∘

Subtract 177^∘ from both sides: 3x = 183^∘

Divide by 3: `x=(183°)/3 = 61°`

Each of the remaining three exterior angles is: 61^∘