Advertisements
Advertisements
प्रश्न
Calculate the number of sides of a regular polygon, if: its interior angle is five times its exterior angle.
Advertisements
उत्तर
Let number of sides of a regular polygon = n
Let exterior angle = x
Then interior angle = 5x
x + 5x = 180°
⇒ 6x = 180°
⇒ x = `180^circ/6 = 30^circ`
∴ Number of sides (n) = `(360°)/30 = 12`
APPEARS IN
संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
Find the number of sides in a regular polygon, if its interior angle is: 135°
Find the number of sides in a regular polygon, if its exterior angle is : `1/3` of right angle
Is it possible to have a regular polygon whose interior angle is : 170°
The sum of interior angles of a regular polygon is twice the sum of its exterior angles. Find the number of sides of the polygon.
Calculate the number of sides of a regular polygon, if: the ratio between its exterior angle and interior angle is 2: 7.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Find number of side in a regular polygon, if it exterior angle is: 36
Is it possible to have a regular polygon whose interior angle is: 155°
What is the measure of each interior angle of a regular hexagon?
