Advertisements
Advertisements
प्रश्न
The ratio between the exterior angle and the interior angle of a regular polygon is 1 : 4. Find the number of sides in the polygon.
Advertisements
उत्तर
Let exterior angle = x° & interior angle = 4x°
∴ 4x + x = 180°
5x = 180°
x = 36°
∴ Each exterior angle = 36°
Let no.of sides = n
∴ `360^circ/"n" = 36^circ`
n = `360^circ/36^circ`
n = 10
APPEARS IN
संबंधित प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: `1 1/5` of a right angle
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
The measure of each interior angle of a regular polygon is five times the measure of its exterior angle. Find :
(i) measure of each interior angle ;
(ii) measure of each exterior angle and
(iii) number of sides in the polygon.
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
In a regular pentagon ABCDE, draw a diagonal BE and then find the measure of:
(i) ∠BAE
(ii) ∠ABE
(iii) ∠BED
The difference between the exterior angles of two regular polygons, having the sides equal to (n – 1) and (n + 1) is 9°. Find the value of n.
The sum of interior angles of a regular polygon is thrice the sum of its exterior angles. Find the number of sides in the polygon.
Find the number of sides in a regular polygon, if its interior angle is: 150°
Find number of side in a regular polygon, if it exterior angle is: 36
Is it possible to have a regular polygon whose exterior angle is: 100°
