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Maharashtra State BoardSSC (English Medium) 9th Standard

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

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Question

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

Sum
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Solution

Let the edge of the cube be l cm.
Total surface area of the cube = 5400 cm2

∴ 6l2 = 5400

⇒ l2 = `5400/6` = 900

⇒ l = `sqrt900` = 30 cm

∴ Surface area of all vertical faces of the cube = 4l2 
= 4 × (30 cm)2 
= 4 × 900 cm2 
= 3600 cm2
Thus, the surface area of all vertical faces of the cube is 3600 cm2.

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Chapter 9: Surface Area and Volume - Practice Set 9.1 [Page 115]

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Balbharati Mathematics 2 [English] Standard 9 Maharashtra State Board
Chapter 9 Surface Area and Volume
Practice Set 9.1 | Q 4. | Page 115

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