Advertisements
Advertisements
Question
Total cost of fencing the park shown in the following figure is Rs 55000. Find the cost of fencing per metre.

Advertisements
Solution
Perimeter of ABCDEFA = Sum of all sides
= AB + BC + CD + DE + EF + FA
= (150 + 100 + 120 + 180 + 270 + 280) m
= 1100 m
Total cost = ₹ 55000 ...[Given]
Now, cost of fencing per metre
= `"Total cost"/"Perimeter"`
= `55000/1100`
= ₹ 50
APPEARS IN
RELATED QUESTIONS
The lengths of the sides of two squares are in the ratio 8:15, find the ratio between their perimeters.
If P denotes perimeter of a rectangle, l denotes its length and b denotes its breadth, find:
l, if P = 38cm and b = 7cm
If P denotes perimeter of a rectangle, l denotes its length and b denotes its breadth, find:
P, if l = 2 m and b = 75cm
The side of a square is of length 20 mm. Find its perimeter in cm.
Find the perimeter of the following figure:

The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 10 m | ? | ? | 120 sq.m |
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| ? | 4 feet | ? | 20 sq.feet |
The area of a rectangular shaped photo is 820 sq.cm. and its width is 20 cm. What is its length? Also find its perimeter
Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:
| Whose card | Length | Width | Perimeter | Area |
| Sanya | 10 cm | 8 cm | ||
| Manav | 11 cm | 44 cm | ||
| Aarushi | 8 cm | 80 square cm | ||
| Kabir | 40 cm | 100 square cm |
Perimeter of an isosceles triangle is 50 cm. If one of the two equal sides is 18 cm, find the third side.
