Advertisements
Advertisements
Question
Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces; find the length of each piece.
Advertisements
Solution
1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m 3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = `240.36/12` = 20.3 m.
APPEARS IN
RELATED QUESTIONS
By how much does the sum of 18.0495 and 34.9644 exceed the sum of 7.6752 and 24.876?
What least number must be added to 89.376 to get 1000?
Subtract:
Rs. 35.74 from Rs. 63.22
Add (giving the answer in metre):
848 cm and 2.9 m
Add (giving the answer in kg):
2.06 kg and 57.864 kg
Add (giving the answer in kg):
778 gm and 1.939 kg
Add (giving the answer in kg):
0.065 kg and 4023 gm
Subtract (giving the answer in kg):
9.462 kg from 15.6 kg
A certain amount of money is distributed among 28 persons. If each person gets Rs. 62.45 and Rs. 5.78 is left, find the original amount of money
What is the decimal form of 500 grams in kilograms?
