Advertisements
Advertisements
प्रश्न
Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces; find the length of each piece.
Advertisements
उत्तर
1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m 3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = `240.36/12` = 20.3 m.
APPEARS IN
संबंधित प्रश्न
Subtract:
Rs. 35.74 from Rs. 63.22
Subtract:
Rs. 0.55 from 121 paise
Subtract (giving the answer in metre):
5.03 m from 19.6 m
Add (giving the answer in kg):
0.065 kg and 4023 gm
Subtract (giving the answer in kg):
4317 gm from 23 kg
A piece of rope is 10 m 67 cm long. Another rope is 16 m 32 cm long. By how much is the second rope longer than the first one?
12 cakes of soap together weigh 5 kg and 604 gm. Find the weight of
(i) One cake in both kg and gramme
(ii) 5 cakes in kg.
What is the decimal form of 500 grams in kilograms?
A length of 1.6 metres is equal to how many centimetres?
If a fabric is 2.75 metres long, what does the decimal 0.75 represent?
