Advertisements
Advertisements
प्रश्न
Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces; find the length of each piece.
Advertisements
उत्तर
1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m 3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = `240.36/12` = 20.3 m.
APPEARS IN
संबंधित प्रश्न
Subtract:
0.43 from 0.97
What least number must be added to 89.376 to get 1000?
Add (giving answer in rupees):
Rs. 5.37 and Rs. 12
Add (giving answer in rupees):
Rs. 24.03 and 532 paise
Add (giving answer in rupees):
8 paise and Rs. 1536
Add (giving the answer in metre):
848 cm and 2.9 m
Subtract (giving the answer in metre):
5.03 m from 19.6 m
Subtract (giving the answer in metre):
428 cm from 1033 m
Find the distance walked by a boy in `1 1/2` hours if he walks at 2.150 km every hour.
The difference between the two numbers is 47.364. If the smaller number is 31.855; find the bigger one.
