Advertisements
Advertisements
Question
Three numbers in A.P. have the sum of 30. What is its middle term?
Options
4
10
16
8
Advertisements
Solution
10
Explanation:
Let the three numbers be a − d, a, and a + d, where a is the middle term, and d is the common difference.
Given that their sum is 30, we have:
(a − d) + a + (a + d) = 30
3a = 30
a = `30/3`
a = 10
So, the middle term a is 10.
APPEARS IN
RELATED QUESTIONS
If Sn1 denotes the sum of first n terms of an A.P., prove that S12 = 3(S8 − S4).
Find the sum of the following arithmetic progressions: 50, 46, 42, ... to 10 terms
The 24th term of an AP is twice its 10th term. Show that its 72nd term is 4 times its 15th term.
For what value of n, the nth terms of the arithmetic progressions 63, 65, 67, ... and 3, 10, 17, ... equal?
The 9th term of an A.P. is equal to 6 times its second term. If its 5th term is 22, find the A.P.
If the sum of P terms of an A.P. is q and the sum of q terms is p, then the sum of p + q terms will be
Q.5
Which term of the AP 3, 15, 27, 39, ...... will be 120 more than its 21st term?
First four terms of the sequence an = 2n + 3 are ______.
The sum of n terms of an A.P. is 3n2. The second term of this A.P. is ______.
