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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

Three identical cubes of side 4 cm are joined end to end. Find the total surface area and lateral surface area of the new resulting cuboid

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Question

Three identical cubes of side 4 cm are joined end to end. Find the total surface area and lateral surface area of the new resulting cuboid

Sum
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Solution

Joint the three identical cubes we get a new cuboid

Length of the cuboid (l) = (4 + 4 + 4) cm

l = 12 cm

Breadth of the cuboid (b) = 4 cm

Height of the cuboid (h) = 4 cm

Total surface area of the new cuboid = 2(lb + bh + lh) sq.units

= 2(12 × 4 + 4 × 4 + 4 × 12)

= 2(48 + 16 + 48) cm

= 2(112) cm2

= 224 cm2

Lateral surface area of the new cuboid = 2(l + b)h sq.units

= 2(12 + 4)4 cm2

= 2 × 16 × 4 cm2

= 128 cm2

∴ T.S.A of the new cuboid = 224 cm2

L.S.A of the new cuboid = 128 cm2

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Chapter 7: Mensuration - Exercise 7.2 [Page 257]

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Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 7 Mensuration
Exercise 7.2 | Q 7 | Page 257

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