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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ९

Three identical cubes of side 4 cm are joined end to end. Find the total surface area and lateral surface area of the new resulting cuboid - Mathematics

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प्रश्न

Three identical cubes of side 4 cm are joined end to end. Find the total surface area and lateral surface area of the new resulting cuboid

बेरीज
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उत्तर

Joint the three identical cubes we get a new cuboid

Length of the cuboid (l) = (4 + 4 + 4) cm

l = 12 cm

Breadth of the cuboid (b) = 4 cm

Height of the cuboid (h) = 4 cm

Total surface area of the new cuboid = 2(lb + bh + lh) sq.units

= 2(12 × 4 + 4 × 4 + 4 × 12)

= 2(48 + 16 + 48) cm

= 2(112) cm2

= 224 cm2

Lateral surface area of the new cuboid = 2(l + b)h sq.units

= 2(12 + 4)4 cm2

= 2 × 16 × 4 cm2

= 128 cm2

∴ T.S.A of the new cuboid = 224 cm2

L.S.A of the new cuboid = 128 cm2

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पाठ 7: Mensuration - Exercise 7.2 [पृष्ठ २५७]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
पाठ 7 Mensuration
Exercise 7.2 | Q 7 | पृष्ठ २५७

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