Question

Three critics review a book. Odds in favour of the book are 5 : 2, 4 : 3 and 3 : 4 respectively for the three critics. Find the probability that all critics are in favour of the book.

Answer 1

I critic `P(E_1) = 5/7`

II critic `P(E_2) = 4/7`

III critic `P(E_3) = 3/7`

P(All in favour) = P(E₁ ∩ E₂ ∩ E₃)

= P(E₁) × P(E₂) × P(E₃)

 = `5/7 xx 4/7 xx 3/7`

= `60/343`