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There is a field whose each side is 40 m. A square flower bed is prepared in its centre leaving a gravel path all around the flower bed. The total cost of laying the flower bed - Mathematics

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Question

There is a field whose each side is 40 m. A square flower bed is prepared in its centre leaving a gravel path all around the flower bed. The total cost of laying the flower bed and gravelling the path at ₹ 1.50 and 60 paise per square meter is ₹ 2126.40. Find the length of the gravel path.

Sum
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Solution

Given: There is a square field with side 40 m. A square flower bed is prepared in its centre leaving a gravel path all around the bed. Cost of laying the flower bed = ₹ 1.50 per m2; cost of gravelling the path = 60 paise (₹ 0.60) per m2. Total cost = ₹ 2126.40.

Step-wise calculation:

1. Let the side of the square flower bed = s m.

Then the width of the gravel path = x = `(40 - s)/2` (m).

2. Area of whole field = 402 = 1600 m2

Area of flower bed = s2.

Area of path = 1600 – s2.

3. Total cost = (cost for bed) + (cost for path)

= 1.50 · s2 + 0.60 · (1600 – s2

= 2126.40

4. Simplify:

(1.50 – 0.60) s2 + 0.60 · 1600 = 2126.40

⇒ 0.90 s2 + 960 = 2126.40

⇒ 0.90 s2 = 2126.40 – 960

⇒ 0.90 s2 = 1166.40

⇒ s2 = `1166.40/0.90`

⇒ s2 = 1296

⇒ s = `sqrt(1296)`

⇒ s = 36 m

5. Path width x = `(40 - 36)/2`

= `4/2`

= 2 m

The gravel path is 2 metres wide.

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Chapter 16: Mensuration - Exercise 16B [Page 326]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 16 Mensuration
Exercise 16B | Q 41. | Page 326
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