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Question
The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?
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Solution
Here `Y = "stress"/"strain"`
According to question, longitudinal stress for rubber and steel are equal
So, `Y ∝ Stress`
`Y_(Steel)/Y_(Rub ber) = (Stress)_(Steel)/(Stress)_(Rub ber)`
∵ `Y_(Steel) > Y_(Rub ber)`
`Y_(Steel)/Y_A > 1`
`(Stress)_(Steel) > (Stress)_(Rub ber)`
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