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Karnataka Board PUCPUC Science Class 11

The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?

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Question

The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?

Short/Brief Note
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Solution

Here `Y = "stress"/"strain"`

According to question, longitudinal stress for rubber and steel are equal

So, `Y ∝ Stress`

`Y_(Steel)/Y_(Rub ber) = (Stress)_(Steel)/(Stress)_(Rub ber)`

∵ `Y_(Steel) > Y_(Rub ber)`

`Y_(Steel)/Y_A > 1`

`(Stress)_(Steel) > (Stress)_(Rub ber)`

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Chapter 9: Mechanical Properties of Solids - Exercises [Page 69]

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NCERT Exemplar Physics Exemplar [English] Class 11
Chapter 9 Mechanical Properties of Solids
Exercises | Q 9.14 | Page 69

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