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Karnataka Board PUCPUC Science 2nd PUC Class 12

The work done to move a charge along an equipotential from A to B ______. cannot be defined as -∫ABE.dl must be defined as -∫ABE.dl is zero. can have a non-zero value. - Physics

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Question

The work done to move a charge along an equipotential from A to B ______.

  1. cannot be defined as `- int_A^B E.dl`
  2. must be defined as `- int_A^B E.dl`
  3. is zero.
  4. can have a non-zero value.

Options

  • a and b

  • b and c

  • c and d

  • a and c

MCQ
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Solution

b and c

Explanation:

The work done by the external agent in shifting the test charge along the dashed line from 1 to 2 is

The external agent does a work `W = - q int_1^2 vecE * vec(dl)` in transporting the test charge q slowly from the positions 1 to 2 in the static electric field.

`W_("ext") = int_1^2 vecF_("ext") * vec(dl) int_1^2 (-qvecE) * vec(dl) = - q int_1^2 vecE * vec(dl)`

We know `V_A - V_B = - int_A^B vecE * vec(dl)`  ......(i)

`W_("electrical") = -ΔU = - qΔV = q(V_A - V_B)`  ......(ii)

Hence from (i) and (ii), `W_("electrical") = q(V_A - V_B) = - qint_A^B vecE * vec(dl)`

If we want to calculate the work done to move a charge along an equipotential from A to B

For equipotential surface VA = VB, hence W = 0

Also electric field is perpendicular to equipotential surface, hence `vecE * vec(dl) => W_("electrical") = 0`

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Equipotential Surfaces
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Chapter 2: Electrostatic Potential And Capacitance - MCQ I [Page 12]

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NCERT Exemplar Physics [English] Class 12
Chapter 2 Electrostatic Potential And Capacitance
MCQ I | Q 2.09 | Page 12

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