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Question
The vertices of a triangle are A(3, 4), B(2, 0), and C(−1, 6). Find the equation of the line containing side BC.
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Solution
Vertices of ΔABC are A(3, 4), B(2, 0) and C(−1, 6).
Equation of the line in two-point form is:
`(y_2 - y_1)/(x_2 - x_1)`
∴ The slope of BC = `(y_2 - y_1)/(x_2 - x_1)`
= `(6 - 0)/(-1 - 2)`
= `(6)/(-3)`
= −2
The equation of the containing side BC
y − y1 = m(x − x1)
y − 0 = −2(x − 2)
y = −2x + 4
∴ 2x + y − 4 = 0
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