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The vertices of a triangle are A(3, 4), B(2, 0), and C(−1, 6). Find the equation of the line containing side BC - Mathematics and Statistics

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प्रश्न

The vertices of a triangle are A(3, 4), B(2, 0), and C(−1, 6). Find the equation of the line containing side BC.

योग
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उत्तर

Vertices of ΔABC are A(3, 4), B(2, 0) and C(−1, 6).

Equation of the line in two-point form is:

`(y_2 - y_1)/(x_2 - x_1)`

∴ The slope of  BC = `(y_2 - y_1)/(x_2 - x_1)`

= `(6 - 0)/(-1 - 2)`

= `(6)/(-3)`

= −2

The equation of the containing side BC

y − y1 = m(x − x1)

y − 0 = −2(x − 2)

y = −2x + 4

∴ 2x + y − 4 = 0

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Equations of Line in Different Forms
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Straight Line - Exercise 5.3 [पृष्ठ ११४]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 5 Straight Line
Exercise 5.3 | Q 8. (a) | पृष्ठ ११४

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