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Question
The vapour pressure of a pure liquid is 0.043 bar at a certain temperature. When a nonvolatile solute is dissolved into it, the vapour pressure of the solution is found to be 0.041 bar. What is the relative lowering of vapour pressure?
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Solution
Given: Vapour pressure of pure liquid `("P"_1^0)` = 0.043 bar
Vapour pressure of the solution (P1) = 0.041 bar
To find: Relative lowering of vapour pressure
Formula: Relative lowering of vapour pressure
`= (Delta "P")/"P"_1^0 = ("P"_1^0 - "P"_1)/"P"_1^0`
Calculation: From formula,
Relative lowering of vapour pressure
`= (Delta "P")/"P"_1^0 = ("P"_1^0 - "P"_1)/"P"_1^0`
`= (0.043 - 0.041)/0.043 = 0.0465`
Relative lowering of vapour pressure is 0.0465.
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