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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

The vapour pressure of a pure liquid is 0.043 bar at a certain temperature. When a nonvolatile solute is dissolved into it, the vapour pressure of the solution is found to be 0.041 bar.

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प्रश्न

The vapour pressure of a pure liquid is 0.043 bar at a certain temperature. When a nonvolatile solute is dissolved into it, the vapour pressure of the solution is found to be 0.041 bar. What is the relative lowering of vapour pressure?

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उत्तर

Given: Vapour pressure of pure liquid `("P"_1^0)` = 0.043 bar
Vapour pressure of the solution (P1) = 0.041 bar

To find: Relative lowering of vapour pressure

Formula: Relative lowering of vapour pressure

`= (Delta "P")/"P"_1^0 = ("P"_1^0 - "P"_1)/"P"_1^0`

Calculation: From formula,

Relative lowering of vapour pressure

`= (Delta "P")/"P"_1^0 = ("P"_1^0 - "P"_1)/"P"_1^0`

`= (0.043 - 0.041)/0.043 = 0.0465`

Relative lowering of vapour pressure is 0.0465.

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Vapour Pressure Lowering
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पाठ 2: Solutions - Very short answer questions

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