Advertisements
Advertisements
प्रश्न
Calculate the mole fraction of solute, if the vapour pressure of pure benzene at a certain temperature is 640 mmHg and the vapour pressure of a solution of a solute in benzene is 600 mmHg.
Advertisements
उत्तर
We can use Raoult's law to calculate the mole fraction of the solute. Raoult's law states:
Where:
- Psolution = 600 mmHg
- Ppure solvent = 640 mmHg
- Xsolvent = mole fraction of the solvent
The mole fraction of the solvent can be expressed as:
Xsolvent = `P_(solution)/P_(pure solvent)`
Substitute the values:
Xsolvent = `600/640` = 0.9375
Now, the mole fraction of the solute (Xsolute) is given by:
Xsolute = 1 − Xsolvent
Substitute the value of Xsolvent:
Xsolute = 1 − 0.9375
= 0.0625
APPEARS IN
संबंधित प्रश्न
Answer the following.
Why vapour pressure of a solvent is lowered by dissolving a nonvolatile solute into it?
The following solution/solvent has maximum vapour pressure _______.
Write the expression for relative lowering of vapour pressure.
Which of the following is NOT a colligative property?
The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.
The vapour pressure of pure solvent and solution are 120 mm Hg and 108 mm Hg respectively. The mole fraction of the solvent in the solution is ____________.
Relative lowering of vapour pressure of a solution of non-volatile solute depend only on ____________.
Which of the following is CORRECT statement?
The vapour pressure of pure benzene (molar mass 78 g/mol) at a certain temperature is 640 mm Hg. A nonvolatile solute of mass 2.315 g is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molar mass of solute is ______.
At a constant volume, a quantity of an ideal gas has a pressure of 700 mm Hg at 300 K. At what pressure, the temperature will be halved?
According to Raoult's law, relative lowering of vapour pressure for a solution containing a nonvolatile solute is equal to ____________.
Which of the following is INCORRECT expression in terms of vapour pressure of pure solvent `("P"_1^0)` and that of solution (P)?
Which of the following changes will cause increase in vapour pressure of 1 molal aqueous KI solution at same temperature?
What will be the molar mass of solute if vapour pressure of pure benzene is 450 mm Hg when 1.5 g of non-volatile solute is added to 30 g of benzene?
(Vapour pressure of solution= 400 mm Hg, Atomic mass C = 12, H = 1)
Relative lowering in vapour pressure depends on _______.
Identify the correct statement from the following:
38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution?
12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is ______.
The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. the mole fraction of B in the solution is ______.
The vapour pressure of 100 g of water reduces from 17.53 mm to 17.22 mm when 17.10 g, of substance X is dissolved in it. Substance X can be ______.
