Advertisements
Advertisements
प्रश्न
Calculate the mole fraction of solute, if the vapour pressure of pure benzene at a certain temperature is 640 mmHg and the vapour pressure of a solution of a solute in benzene is 600 mmHg.
Advertisements
उत्तर
We can use Raoult's law to calculate the mole fraction of the solute. Raoult's law states:
Where:
- Psolution = 600 mmHg
- Ppure solvent = 640 mmHg
- Xsolvent = mole fraction of the solvent
The mole fraction of the solvent can be expressed as:
Xsolvent = `P_(solution)/P_(pure solvent)`
Substitute the values:
Xsolvent = `600/640` = 0.9375
Now, the mole fraction of the solute (Xsolute) is given by:
Xsolute = 1 − Xsolvent
Substitute the value of Xsolvent:
Xsolute = 1 − 0.9375
= 0.0625
APPEARS IN
संबंधित प्रश्न
Answer the following.
How vapour pressure lowering is related to a rise in the boiling point of solution?
The following solution/solvent has maximum vapour pressure _______.
Write the expression for relative lowering of vapour pressure.
Which of the following is NOT a colligative property?
The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.
Relative lowering of vapour pressure of a solution of non-volatile solute depend only on ____________.
Which of the following is CORRECT for a solution containing non-volatile solute in it?
In an experiment, 1 g of a non-volatile solute was dissolved in 100 g of acetone (molar mass = 58 g mol−1) at 298 K. The vapour pressure of the solution was found to be 192.5 mm Hg. The molecular weight of the solute is (vapour pressure of acetone = 195 mm Hg) ____________ g mol−1.
Which of the following is CORRECT statement?
The vapour pressure of pure benzene (molar mass 78 g/mol) at a certain temperature is 640 mm Hg. A nonvolatile solute of mass 2.315 g is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molar mass of solute is ______.
Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of ____________.
Which of the following is INCORRECT expression in terms of vapour pressure of pure solvent `("P"_1^0)` and that of solution (P)?
The vapour pressure of water at 20°C is 17 mm Hg. The vapour pressure of solution containing 2.8 g urea in 50 g of water is ____________.
What will be the molar mass of solute if vapour pressure of pure benzene is 450 mm Hg when 1.5 g of non-volatile solute is added to 30 g of benzene?
(Vapour pressure of solution= 400 mm Hg, Atomic mass C = 12, H = 1)
Identify the correct statement from the following:
38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution?
12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is ______.
The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. the mole fraction of B in the solution is ______.
Which of the following solutions will have the maximum lowering of vapour pressure at 300 K?
The vapour pressure of 100 g of water reduces from 17.53 mm to 17.22 mm when 17.10 g, of substance X is dissolved in it. Substance X can be ______.
