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Answer the following. How vapour pressure lowering is related to a rise in the boiling point of solution? - Chemistry

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प्रश्न

Answer the following.

How vapour pressure lowering is related to a rise in the boiling point of solution?

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उत्तर

  1. At the boiling point of a liquid, its vapour pressure is equal to 1 atm.
  2. In order to reach boiling point, the solution and solvent must be heated to a temperature at which their respective vapour pressures attain 1 atm.
  3. At any given temperature the vapour pressure of a solution is lower than that of pure solvent. Hence, the vapour pressure of solution needs a higher temperature to reach 1 atm than that of needed for vapour pressure of solvent. Therefore, vapour pressure lowering causes a rise in the boiling point of a solution.
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Vapour Pressure Lowering
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अध्याय 2: Solutions - Exercises [पृष्ठ ४५]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 2 Solutions
Exercises | Q 3.1 | पृष्ठ ४५

संबंधित प्रश्न

Answer the following.

Why vapour pressure of a solvent is lowered by dissolving a nonvolatile solute into it?


The following solution/solvent has maximum vapour pressure _______.


Write the expression for relative lowering of vapour pressure.


The vapour pressure of solvent decreases by 1 O mm Hg, if mole fraction of non-volatile solute is 0.2. Calculate vapour pressure of solvent.


Relative lowering of vapour pressure of a solution of non-volatile solute depend only on ____________.


Which of the following is CORRECT for a solution containing non-volatile solute in it?


In an experiment, 1 g of a non-volatile solute was dissolved in 100 g of acetone (molar mass = 58 g mol−1) at 298 K. The vapour pressure of the solution was found to be 192.5 mm Hg. The molecular weight of the solute is (vapour pressure of acetone = 195 mm Hg) ____________ g mol−1.


Which of the following is CORRECT statement?


The vapour pressure of pure benzene (molar mass 78 g/mol) at a certain temperature is 640 mm Hg. A nonvolatile solute of mass 2.315 g is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molar mass of solute is ______.


At a constant volume, a quantity of an ideal gas has a pressure of 700 mm Hg at 300 K. At what pressure, the temperature will be halved?


According to Raoult's law, relative lowering of vapour pressure for a solution containing a nonvolatile solute is equal to ____________.


Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of ____________.


Which of the following is INCORRECT expression in terms of vapour pressure of pure solvent `("P"_1^0)` and that of solution (P)?


Which of the following changes will cause increase in vapour pressure of 1 molal aqueous KI solution at same temperature?


What will be the molar mass of solute if vapour pressure of pure benzene is 450 mm Hg when 1.5 g of non-volatile solute is added to 30 g of benzene?
(Vapour pressure of solution= 400 mm Hg, Atomic mass C = 12, H = 1)


Relative lowering in vapour pressure depends on _______.


12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is ______.


The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. the mole fraction of B in the solution is ______.


Which of the following solutions will have the maximum lowering of vapour pressure at 300 K?


Calculate the mole fraction of solute, if the vapour pressure of pure benzene at a certain temperature is 640 mmHg and the vapour pressure of a solution of a solute in benzene is 600 mmHg.


State and explain Raoult's law for the solution of non-volatile solutes.


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