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The value of the determinant ∆ = |(sin223∘,sin267∘,cos180∘),(-sin267∘,-sin223∘,cos2180∘),(cos180∘,sin223∘,sin267∘)| = ______. - Mathematics

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Question

The value of the determinant ∆ = `|(sin^2 23^circ, sin^2 67^circ, cos180^circ),(-sin^2 67^circ, -sin^2 23^circ, cos^2 180^circ),(cos180^circ, sin^2 23^circ, sin^2 67^circ)|` = ______.

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Solution

The value of the determinant ∆ = `|(sin^2 23^circ, sin^2 67^circ, cos180^circ),(-sin^2 67^circ, -sin^2 23^circ, cos^2 180^circ),(cos180^circ, sin^2 23^circ, sin^2 67^circ)|` = 0.

Explanation:

Apply C1 → C1 + C2 + C3.

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Chapter 4: Determinants - Solved Examples [Page 75]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 4 Determinants
Solved Examples | Q 14 | Page 75

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