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The determinant ∆ = |23+35515+465103+115155| is equal to ______. - Mathematics

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Question

The determinant ∆ = `|(sqrt(23) + sqrt(3), sqrt(5), sqrt(5)),(sqrt(15) + sqrt(46), 5, sqrt(10)),(3 + sqrt(115), sqrt(15), 5)|` is equal to ______.

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Solution

The determinant ∆ = `|(sqrt(23) + sqrt(3), sqrt(5), sqrt(5)),(sqrt(15) + sqrt(46), 5, sqrt(10)),(3 + sqrt(115), sqrt(15), 5)|` is equal to 0.

Explanation:

Taking `sqrt(5)` common from C2 and C3 and applying `"C"_1 -> "C"_3 - sqrt(3)` C2, we get the desired result.

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Chapter 4: Determinants - Solved Examples [Page 75]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 4 Determinants
Solved Examples | Q 13 | Page 75

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