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Question
The total cost of certain piece of cloth was ₹ 2,100. During special sale time, the shopkeeper offered 2 m extra cloth for free thus reducing the price of cloth per metre by ₹ 120. What was the original per metre price of cloth and its length?
Sum
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Solution
Let original length be L metres and original price be P per metre.
L × P = 2100 ⇒ `P = 2100/L`
New length = L + 2
New price per metre = `2100/(L + 2)`
Given: Pnew = Pold – 120.
`2100/L - 2100/(L + 2) = 120`
`17.5/L - 17.5/(L + 2) = 1`
`17.5 ((L + 2 - L)/(L(L + 2))) = 1`
`35/(L^2 + 2L) = 1` ⇒ L2 + 2L – 35 = 0
Factorizing: (L + 7)(L – 5) = 0.
Since length cannot be negative, L = 5 m.
Original price P = `2100/5` = 420.
Original price was 420 per metre and length was 5 m.
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