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The table given below shows the frequency distribution of the monthly wages of the employees of a company: Wages (in ₹) 400 – 499 500 – 599 600 – 699 700 – 799 800 – 899 No. of employees 12 17 13 8 3 - Mathematics

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Question

The table given below shows the frequency distribution of the monthly wages of the employees of a company:

Wages (in ₹) 400 – 499 500 – 599 600 – 699 700 – 799 800 – 899
No. of employees 12 17 13 8 3

Use this table and find: 

  1. The lower limit of the fourth class; 
  2. The upper limit of the fifth class; 
  3. The class boundaries of second class; 
  4. The class mark of first class; 
  5. The class-size of third class.
Sum
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Solution

Given: Table of wages and frequencies:

400 – 499 : 12

500 – 599 : 17

600 – 699 : 13

700 – 799 : 8

800 – 899 : 5

Step-wise calculation:

i. Lower limit of the fourth class:

Fourth class = 700 – 799

Lower limit = 700 the stated lower class limit.

ii. Upper limit of the fifth class:

Fifth class = 800 – 899

Upper limit = 899 the stated upper class limit.

iii. Class boundaries of the second class:

Second class (stated limits) = 500 – 599

Convert to continuous boundaries by subtracting/adding 0.5:

Lower boundary

= 500 – 0.5

= 499.5

Upper boundary

= 599 + 0.5

= 599.5

So, class boundaries = 499.5 – 599.5.

iv. Class mark of the first class:

First class = 400 – 499

Class mark = `(400 + 499)/2`

= `899/2`

= 449.5

v. Class-size of the third class:

Third class = 600 – 699 true boundaries 599.5 – 699.5

Class-size = 699.5 – 599.5 = 100

Equivalently, 699 – 600 + 1 = 100 for inclusive discrete classes.

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Chapter 15: Statistics - Exercise 15A [Page 289]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 15 Statistics
Exercise 15A | Q 11. | Page 289
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