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The surface area of a solid metallic sphere is 2464 cm2. It is melted and recast into solid right circular cones of radius 3.5 cm and height 7 cm. Calculate: the radius of the sphere.

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Question

The surface area of a solid metallic sphere is 2464 cm2. It is melted and recast into solid right circular cones of radius 3.5 cm and height 7 cm. Calculate:

  1. the radius of the sphere.
  2. the number of cones recast. (Take π = `22/7`)
Sum
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Solution

i. Total surface area of the sphere = 4πr2, where r is the radius of the sphere.

Thus,

4πr2 = 2464 cm2

`=> 4 xx 22/7 xx r^2 = 2464`

`=>` r2 = 196

`=>` r = 14 cm

∴ R = 14 cm

ii. Volume of sphere melted = `4/3 piR^3`

= `4/3 xx pi xx 14 xx 14 xx 14`

Radius of each cone recasted = r = 3.5 cm

Height of each cone recasted = h = 7 cm

∴ Volume of each cone recasted = `1/3 pir^2h`

= `1/3 xx pi xx 3.5 xx 3.5 xx 7`

∴ Number of cones recasted

= `"Volume of sphere melted"/"Volume of each cone formed"`

= `(4/3 xx pi xx 14 xx 14 xx 14)/(1/3 xx pi xx 3.5 xx 3.5 xx 7)`

= `(4 xx 14 xx 14 xx 14)/(3.5 xx 3.5 xx 7)`

= 4 × 4 × 4 × 2

= 128

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Chapter 20: Cylinder, Cone and Sphere - EXERCISE 20 (D) [Page 315]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 20 Cylinder, Cone and Sphere
EXERCISE 20 (D) | Q 9. | Page 315

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