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Question
The sum of two numbers is 4500. If 10% of one number is 12.5% of the other, find the numbers.
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Solution
Let the two numbers be x and y, where x + y = 4500. The condition states:
10% of x = 12.5% of y
Step 1: Express the percentages as fractions
`10/100x = 12.5/100y`
Simplify the fractions: `1/10x=1/8y`
Multiply through by 80 (LCM of 10 and 8) to eliminate fractions:
8x = 10y
Step 2: Relate x and y
`x = 10/8y = 5/4 y`
From 8x = 10y, solve for x in terms of y:
`x=10/8 y = 5/4 y`
Step 3: Use the sum condition
Substitute `x=5/4y` into x+y = 4500:
`5/4 y+y = 4500`
Combine terms: `5/4y+4/4y=4500`
Multiply through by 4: 9y = 18000
Solve for y: `y = 18000/9 = 2000`
Using x + y = 4500
x = 4500 − y = 4500 − 2000 = 2500
x = 2500 and y = 2000
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