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Question
The sum of two numbers is 10 and the sum of their squares is 68. Find the product of the numbers.
Sum
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Solution
Given:
- The sum of two numbers x and y is 10, i.e., x + y = 10.
- The sum of their squares is 68, i.e., x2 + y2 = 68.
Step-wise calculation:
1. Start from the square of the sum:
(x + y)2 = 102
(x + y)2 = 100
Expanding the left side:
x2 + y2 + 2xy = 100
2. Substitute x2 + y2 = 68:
68 + 2xy = 100
3. Solve for the product xy:
2xy = 100 – 68
2xy = 32
xy = `32/2`
xy = 16
The product of the two numbers is 16.
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Chapter 3: Expansions - Exercise 3B [Page 73]
