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Question
The sum of first n odd natural numbers is n2.
Options
True
False
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Solution
This statement is True.
Explanation:
Given: First n odd natural numbers
Odd natural numbers will be = 2n – 1
As we know, sum of odd natural numbers
= `(2 xx n xx (n + 1))/2 - n`
= n(n + 1) – n
= n2 + n – n
= n2
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RELATED QUESTIONS
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
How many numbers lie between squares of the given numbers?
12 and 13
How many numbers lie between squares of the given numbers?
25 and 26
How many numbers lie between squares of the following numbers?
99 and 100
Square of the number 7 is _________
The next two numbers in the number pattern 1, 4, 9, 16, 25 ... are ______.
The sum of first six odd natural numbers is ______.
