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प्रश्न
The sum of first n odd natural numbers is n2.
विकल्प
True
False
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उत्तर
This statement is True.
Explanation:
Given: First n odd natural numbers
Odd natural numbers will be = 2n – 1
As we know, sum of odd natural numbers
= `(2 xx n xx (n + 1))/2 - n`
= n(n + 1) – n
= n2 + n – n
= n2
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संबंधित प्रश्न
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Observe the following pattern and supply the missing number.
112 = 121
1012 = 10201
101012 = 102030201
10101012 = _____
____2 = 10203040504030201.
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding find the sum:
1 + 3 + 5 + 7 + 9
Express 49 as the sum of 7 odd numbers.
How many numbers lie between squares of the given numbers?
12 and 13
Square of the number 7 is _________
64 is the square number of __________
Is 24 a square number?
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
