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The Sum of First N Terms of an A.P. is 3n2 + 4n. Find the 25th Term of this A.P. - Mathematics

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Question

The sum of first n terms of an A.P. is 3n2 + 4n. Find the 25th term of this A.P.

 
Sum
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Solution

\[S_n = 3 n^2 + 4n\]

We know

\[a_n = S_n - S_{n - 1} \]
\[ \therefore a_n = 3 n^2 + 4n - 3 \left( n - 1 \right)^2 - 4\left( n - 1 \right)\]
\[ \Rightarrow a_n = 6n + 1\]

\[a_{25} = 6\left( 25 \right) + 1 = 151\]

 

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Chapter 5: Arithmetic Progression - Exercise 5.6 [Page 53]

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RD Sharma Mathematics [English] Class 10
Chapter 5 Arithmetic Progression
Exercise 5.6 | Q 41 | Page 53

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