Advertisements
Advertisements
Question
The resistance of filament of an electric heater is 500 Ω It is operated at 200V for 1 hour daily. Calculate the current drawn by the heater and the energy consumed in joule.
Advertisements
Solution
Given: R= 500 Ω, V = 200 volt.
Total time = t = 1 × 30h = 30h = 30 × 60 = 60 s = 108000s.
Current drawn by the heater I = `"V"/"R" = 200/500 = 0.4` A
The energy consumed (in joule) = `"V"^2/"R" "t"`
`= (200)^2/500 xx 108000`
= 8640000 J.
APPEARS IN
RELATED QUESTIONS
1 kWh = ________ J
Two bulbs are rated 60 W, 220 V and 60 W, 110 V respectively. Calculate the ratio of their
resistances
An electric bulb of resistance 500 Ω draws current 0.4 A from the source. Calculate:
- the power of bulb and
- the potential difference at its end.
What is the resistance of an appliance rated at V volt, P watt?
An Electric bulb is marked 100 W, 230 V. What current does it take?
1 kWh is equal to:
What is the commercial unit of electrical energy?
A conductor of 10 Ω is connected across a 6 V ideal source. The power supplied by the source to the conductor is ______.
