Advertisements
Advertisements
Question
The resistance of filament of an electric heater is 500 Ω It is operated at 200V for 1 hour daily. Calculate the current drawn by the heater and the energy consumed in joule.
Advertisements
Solution
Given: R= 500 Ω, V = 200 volt.
Total time = t = 1 × 30h = 30h = 30 × 60 = 60 s = 108000s.
Current drawn by the heater I = `"V"/"R" = 200/500 = 0.4` A
The energy consumed (in joule) = `"V"^2/"R" "t"`
`= (200)^2/500 xx 108000`
= 8640000 J.
RELATED QUESTIONS
What is the SI unit of (i) electric energy, and (ii) electric power?
A simple electric circuit has a 30 V battery and a resistor ot 60 o. What will be the current in the circuit? The resistance of the oonnecting wires is negligible.
Why does not the heating coil produce any visible light? in an electric stove.
An electric bulb is marked 100 W, 230 V. What does this mean?
State the reason why, in a three pin plug, the earth pin is longer and thicker than the other two.
I ampere of current is passed through a resistor of resistance R ohm for time t second. Obtain expression for
(i) the electrical energy, and
(ii) the electrical power spent.
