Advertisements
Advertisements
प्रश्न
The resistance of filament of an electric heater is 500 Ω It is operated at 200V for 1 hour daily. Calculate the current drawn by the heater and the energy consumed in joule.
Advertisements
उत्तर
Given: R= 500 Ω, V = 200 volt.
Total time = t = 1 × 30h = 30h = 30 × 60 = 60 s = 108000s.
Current drawn by the heater I = `"V"/"R" = 200/500 = 0.4` A
The energy consumed (in joule) = `"V"^2/"R" "t"`
`= (200)^2/500 xx 108000`
= 8640000 J.
संबंधित प्रश्न
State two factors on which the electrical energy consumed by an electrical appliance depends.
Which uses more energy: a 250 W TV set in 1 hour or a 1200 W toaster in 10 minutes?
State the position of heating element with respect to principal focus of concave reflector and give reason for choosing this position.
What is ‘Rating’ of an electric appliance?
What is the order of current drawn by appliances connected to the ‘light circuit’ of a household?
What is the function of the split rings in a d.c. motor?
State (i) the S. I. unit, (ii) the household unit, of electrical energy. How are these units related?
A family uses a light bulb of 100W, a fan of 100W, and a heater of 1000W, each for 8 hours a day. If the cost of electricity is Rs. 2 per unit, what is the expenditure to the family per day, on electricity?
