Advertisements
Advertisements
Question
The relation between the radius of the sphere and the edge length in the body-centred cubic lattice is given by the formula ______.
Options
`sqrt(3)r` = 4a
r = `sqrt(3)/a xx 4`
r = `sqrt(3)/4a`
r = `sqrt(2)/4 xx a`
Advertisements
Solution
The relation between radius of sphere and edge length in body centered cubic lattice is given by formula `underlinebb(r = sqrt(3)/4a)`.
APPEARS IN
RELATED QUESTIONS
Answer the following in one or two sentences.
Which of the three types of packing used by metals makes the most efficient use of space and which makes the least efficient use?
Answer the following in brief.
Calculate the packing efficiency of metal crystal that has simple cubic structure.
Answer the following in brief.
Cesium chloride crystallizes in a cubic unit cell with Cl– ions at the corners and a Cs+ ion in the center of the cube. How many CsCl molecules are there in the unit cell?
Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?
The density of iridium is 22.4 g/cm3. The unit cell of iridium is fcc. Calculate the radius of iridium atom. Molar mass of iridium is 192.2 g/mol.
An element has a bcc structure with a unit cell edge length of 288 pm. How many unit cells and a number of atoms are present in 200 g of the element? (1.16 × 1024, 2.32 × 1024)
Calculate the packing efficiency for bcc lattice.
In case of hcp structure, how are spheres in first, second and third layers arranged?
A substance crystallizes in fcc structure. The unit cell edge length is 367.8 pm. Calculate the molar mass of the substance if its density is 21.5 g/cm3.
Identify the INCORRECT match.
A compound of X and Y crystallizes in ccp structure in which the X atoms occupy the lattice points at the corners of cube and Y atoms occupy the centres of each of the cube faces. The formula of this compound is ____________.
The total volume occupied by particles m simple cubic unit cell is ____________.
The number of particles in 1 g of a metallic crystal is equal to ____________.
The vacant space in simple cubic lattice is ____________.
Which of the following contains the highest number of atoms?
The percentage of vacant space of bcc unit cell is ____________.
1 mol of CO2 contains ____________.
Atoms of elements A and B crystallize in hep lattice to form a molecule. Element A occupies 2/3 of tetrahedral voids, the formula of molecule is ______.
Copper crystallizes as face centered cubic lattice, with edge length of unit cell 361 pm. Calculate the radius of copper atom.
What is the percentage of void space in bcc type of in unit cell?
An element crystallizes in a bee lattice with cell edge of 500 pm. The density of the element is 7.5 g cm-3. How many atoms are present in 300 g of metal?
Gold crystallizes in face centred cubic structure. If atomic mass of gold is 197 g mol-1, the mass of unit cell of gold is ______.
The packing efficiency of bcc is ______.
A compound has a hep structure. Calculate the number of voids in 0.4 mol of it.
Find the edge length of bcc unit cell if radius of metal atom is 126 pm.
