Advertisements
Advertisements
Question
Answer the following in brief.
Cesium chloride crystallizes in a cubic unit cell with Cl– ions at the corners and a Cs+ ion in the center of the cube. How many CsCl molecules are there in the unit cell?
Advertisements
Solution
Given: Cl– ions are present at the corners of the cube. Cs+ ion is at the center of the cube.
To find: Number of CsCl molecules in the unit cell
Calculation:
i. Cl– ions are present at the 8 corners. The contribution of each corner particle to the unit cell is 1/8. Hence, the number of Cl– ions that belong to the unit cell = 8 × (1/8) = 1
ii. Cs+ ion is at the center of the unit cell. The contribution of a particle at the center to the unit cell is 1. Hence, the number of Cs+ ions that belong to the unit cell = 1
There is one Cl– ion and one Cs+ ion in the unit cell.
Hence, the number of CsCl molecules in the unit cell = 1.
Number of CsCl molecules in the unit cell = 1.
APPEARS IN
RELATED QUESTIONS
Answer the following in one or two sentences.
Which of the three types of packing used by metals makes the most efficient use of space and which makes the least efficient use?
Answer the following in one or two sentences.
Mention two properties that are common to both hcp and ccp lattices.
Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?
Aluminium crystallizes in a cubic close-packed structure with a unit cell edge length of 353.6 pm. What is the radius of Al atom? How many unit cells are there in 1.00 cm3 of Al?
A substance crystallizes in fcc structure. The unit cell edge length is 367.8 pm. Calculate the molar mass of the substance if its density is 21.5 g/cm3.
A compound is formed by elements A and B. This crystallizes in the cubic structure when atoms A are at the comers of the cube and atoms B are at the centre of the body. The simplest formula of the compounds is ____________.
Identify the INCORRECT match.
The total volume occupied by particles m simple cubic unit cell is ____________.
The vacant space in simple cubic lattice is ____________.
Which of the following contains the highest number of atoms?
The percentage of vacant space of bcc unit cell is ____________.
Which among the following crystal structures the edge length of unit cell is equal to twice the radius of one atom?
What is the edge length of fcc type of unit cell having density and atomic mass 6.22 g cm−3 and 60 g respectively?
Atoms of elements A and B crystallize in hep lattice to form a molecule. Element A occupies 2/3 of tetrahedral voids, the formula of molecule is ______.
Copper crystallizes as face centered cubic lattice, with edge length of unit cell 361 pm. Calculate the radius of copper atom.
Copper crystallises with fee unit cell. If the radius of copper atom is 127.8 pm, calculate the density of copper? (At. mass: Cu = 63.55 g mol-1)
What is the percentage of void space in bcc type of in unit cell?
An element crystallizes in a bee lattice with cell edge of 500 pm. The density of the element is 7.5 g cm-3. How many atoms are present in 300 g of metal?
Silver crystallizes in face centred cubic structure, if radius of silver atom is 144.5 pm. What is the edge length of unit cell?
Find the edge length of bcc unit cell if radius of metal atom is 126 pm.
