Question

The rainfall on a certain day was 6 cm. How many litres of water fell on 3 hectares of field on that day?

Answer 1

The rainfall on a certain day = 6 cm

\[ = 6 \times \frac{1}{100}m ( \because 1 m = 100 cm)\]

 = 0 . 06 m

Area of the field = 3 hectares

\[\text { We know that 1 hectare = 10000  }m^2 \]

\[\text { i . e . , 3 hectares = } 3 \times 10000 m^2 = 30000 m^2 \]

\[\text { Thus, volume of rain water that fell in the field = (area of the field) } \times (\text { height of rainfall)  }= 30000 \times 0 . 06 = 1800 m^3 \]

Since 1 m^3 = 1000 L, we have: 

\[1800 m^3 = 1800 \times 1000 L = 1800000 L = 18 \times 100000 L = 18 \times {10}^5 L\]

\[ \therefore \text { On that day, 18 } \times {10}^5 \text { L of rain water fell on the field } .\]