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Question
Find the length of the largest pole that can be placed in a room of dimensions 12 m × 4 m × 3 m.
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Solution
We have ΔACF, in which ∠C = 90°, CF = 3 m and AC = `sqrt((12)^2 + (4)^2)` m
The length of the largest pole = Length of diagonal of cuboid
⇒ (AF)2 = (AC)2 + (CF)2
⇒ (AF)2 = (12)2 + (4)2 + (3)2
⇒ `AF = sqrt(144 + 16 + 9)`
= `sqrt(169)`
= 13 m
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