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The P.M.F. of a Random Variable X is P ( X ) = 1 5 , for X = I, 2, 3, 4, 5 = 0 , Otherwise. Find E(X). - Mathematics and Statistics

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Question

The p.m.f. of a random variable X is
`"P"(x) = 1/5` , for x = I, 2, 3, 4, 5 
        = 0 , otherwise.
Find E(X).

Sum
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Solution

E(X) = `sum_(i = 1)^5  x."P"(x)`

= `1 xx 1/5 + 2 xx 1/5 xx 3 xx 1/5 + 4 xx 1/5 + 5 xx 1/5`

= `15/5`

= 3

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