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Karnataka Board PUCPUC Science Class 11

The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

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Question

The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

Numerical
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Solution

Given

pH = 3.76

it is known that

pH =  -log[`"H"^(+)`]

`=> log["H"^+] = -"pH"` 

`=> ["H"^(+)] = "antilog" (-"pH")`

`= "antilog" (-3.76)`

`= 1.74 xx 10^(-4) "M"`

Hence, the concentration of hydrogen ion in the given sample of vinegar is 1.74 × 10–4M.

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Chapter 6: Equilibrium - EXERCISES [Page 236]

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NCERT Chemistry Part 1 and 2 [English] Class 11
Chapter 6 Equilibrium
EXERCISES | Q 7.42 | Page 236

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