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Question
The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.
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Solution
c = 0.1M
pH = 2.34
−log[H+] = pH
−log[H+] = 2.34
[H+] = 4.5 × 10−3
Also,
[H+] = cα
4.5 × 10−3 = 0.1 × α
`(4.5 xx 10^(-3))/0.1` = α
α = 4.5 × 10−3 = 0.045
Then,
Ka = cα2
= 0.1 × (45 × 10−3)2
= 202.5 × 10−6
= 2.02 × 10−4
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